Web3a2+2a-1/6a3-5a2-8a+3 Final result : -a3 - 12a2 - 36a + 18 ————————————————————— 6 Step by step solution : Step 1 … Web28 feb. 2024 · If a and b are positive integers and (2^a)^b = 23, what is the value of 2^a*2^b? A) 6 B) 8 C) 16 D) 32 E) 64 (2^a)^b = 2^3 =>2^ab = 2^3 ab = 3 if a = 1 then b = 3 or if a=3 then b=1 2^a*2^b = 2^ (a+b) = 2^4 = 16 Answer C hsbinfy Manager Joined: 02 Mar 2012 Posts: 211

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WebThis can be done by using Sridharacharya Formula. The roots of a quadratic equation a x 2 + b x + c are. − b ± b 2 − 4 a c 2 a. Thus, a = 6 ± 6 2 + 4 2. a = 3 ± 10. Now, a 2 + a − 2 = … WebFirst, I found the homogeneous solution: $$ a_n^{(h)} = r^2 - 3r + 2r \\ (r-2)(r-1) = 0 ... Stack Exchange Network Stack Exchange network consists of 181 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. liteneasy wa

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Web15 apr. 2013 · The roots, denoted by r and s, are 2 and 1, respectively. By the Distinct Roots Theorem, the sequence satisfies the following equation a n = C ⋅ r n + D ⋅ s n = C ⋅ 2 n + D. With the initial terms ( a 0 = 2 and a 1 = 3 ), C and D can be solved for by the following equations: a 0 = C ⋅ 2 0 + D = C + D = 2 a 1 = C ⋅ 2 1 + D = 2 C + D = 3 Web9 mrt. 2024 · 7a + (1/3a) = 6. Formula used: (a + b) 2 = a 2 + b 2 + 2ab. Calculation: Multiply by 3/7 both sides. ⇒ 7a × 3/7 + 1/(3a × 7/3) = 6 × (3/7) ⇒ 3a + (1/7a) = 18/7. Squaring … Web1+3a2-3a-a3 Final result : (a - 1)3 Reformatting the input : Changes made to your input should not affect the solution: (1): "a3" was replaced by "a^3". 1 more similar … liteneasy winter menu