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Then show that a2 – 4a+ 7i 0. hence find a5

Splet04. nov. 2024 · Hence Solve the system of equations; x - 2y = 10 2x - y - z = 8 -2y + z = 7 class-12 Share It On 1 Answer +2 votes answered Nov 4, 2024 by Darshee (49.8k points) selected Nov 16, 2024 by Aanchi Best answer A = 1 (−1 − 2) − 2 (−2 − 0) = −3 + 4 = 1 A is non-singular, therefore A−1 exists The given equations can be written as: Splet30. avg. 2024 · Best answer We have, Therefore, A2 – 4A + 7I A2 = 4A – 7I Thus A3 = A.A2 = A (4A – 7I) = 4 (4A – 7I) – 7A = 16A – 28I – 7A = 9A – 28I and so A5 = A3A2 = (9A – …

If , show that A 2 – 5A + 7I = O. Hence find A –1

SpletA 2 = 1 12 -4 1-4A = -8 -12 4 -8 7I = 7 0 0 7 add these three values u will get 0. 0 Splet30. mar. 2024 · Example 26 Show that the matrix A = [ 8 (2& 3@1 &2)] satisfies the equation A2 – 4A + I = O, where I is 2 × 2 identity matrix and O is 2 × 2 zero matrix. Using this … powerapps user fullname 姓名逆になる https://xcore-music.com

Find $A^5- 4A^4-7 A^3+11 A^2-A-10I$ in terms of A using Cayley …

Splet26. sep. 2015 · [-1 2 ] then show that A 2 + 4A +7I = 0. Using this result find A 3 Share with your friends 2 Follow 0 Pooja Khanna, Meritnation Expert added an answer, on 26/9/15 … SpletYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Let A be an (n × n) matrix which satisfies the equation A2 ? 2A + I = … Splet19. jan. 2024 · Show that `A =[{:(5,3),(-1,-2):}]` satisfies the equation `A^(2)-3A-7I=0` and hence find the value of `A^(-1)` powerapps user .email

Let A = 2 3 - 1 2 Then show that A^2 - 4A + 71 = 0 . Using this ...

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Then show that a2 – 4a+ 7i 0. hence find a5

linear algebra - Compute $A^5-4A^4-7A^3+11A^2-A-10I$ for $A

Splet30. apr. 2024 · Here your question is "prove that A has an inverse ". For this you have to show that d e t ( A) ≠ 0. Now since A satisfies the polynomial equation x 2 − 3 x + 1 = 0 … Splet19. feb. 2012 · So, the characteristic polynomial of A is p ( t) = t 2 − 4 t − 5. You are interested in the polynomial P ( t) = t 5 − 4 t 4 − 7 t 3 + 11 t 2 − t − 10, evaluated at A. We …

Then show that a2 – 4a+ 7i 0. hence find a5

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SpletIf , show that A2– 5A + 7I = O. Hence find A–1. We have A2= A.A = . So A2– 5A + 7I = Hence A2– 5A + 7I = 0 ∴A.A – 5A = -7I Now post multiply with A-1 So A.A.A-1-5A.A-1= -7I.A-1 … SpletQuestion From - NCERT Maths Class 12 Chapter 3 MISCELLANEOUS EXERCISE Question – 8 MATRICES CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-If `A=[3 1-1 2]` , ...

SpletAs in the hint, if A~x= ~x, then multiplying both sides on the left by A 1, and also by the scalar 1 gives 1~x= A 1~x: Therefore 1is an eigenvalue for A , since ~x6=~0. 26. Show … Splet23. mar. 2024 · Find the adjoint of the matrix A = (A.I.C.B.S.E. 2010) Solution: Here A = Now A 11 = Co-factor of 2 = 3, A 12 = Co-factor of – 1 = – 4, A 21 = Co-factor of 4 = 1 and …

SpletThe correct option is D5 I 3Find the value of A 2 - 4 A:Given that A = 1 2 2 2 1 2 2 2 1A 2 = 1 2 2 2 1 2 2 2 1 1 2 2 2 1 2 2 2 1 = 9 8 8 8 9 8 8 8 94 A = 4 1 2 2 2 1 2 2 2 1 = 4 8 8 8 4 8 8 8 … Splet03. apr. 2024 · a 2 + 8 = 4a Formula used: (a + b) 2 = a 2 + b 2 + 2ab Calculation: a 2 + 8 = 4a Squaring on both side ⇒ (a 2 + 8) 2 = (4a) 2 ⇒ a 4 + 16a 2 + 64 = 16a 2 ⇒ a 4 = – 64 ----1 a …

Splet04. jun. 2014 · If A = , show that A 2 - 6A + 17I = 0. Hence, find A-1. Asked by Topperlearning User 04 Jun, 2014, 01:23: PM Expert Answer We are given that A = . Now, A 2 - 6A + 17I …

SpletAnswer: If A3 −A2 +A−I= 0, then (A2 −A+I)A= A3 −A2 +A= I= A3 −A2 +A= A(A2 −A+I) so A−1 = A2 −A+I. ♣ (b): If Ais a square matrix satisfying A7 = 0, find (I−A)−1 in terms of A. … tower massingtowermas hotel sibuSpletHence proved. Given: A 2 − 5 A + 7 I = 0. ⇒ A 2 = 5 A − 7 I ... (1) ⇒ A 3 = A ( 5 A − 7 I) (Multilpying by A on both sides) ⇒ A 3 = 5 A 2 − 7 A I. ⇒ A 3 = 5 ( 5 A − 7 I) − 7 A [From … powerapps user directory